$\text{ Let the observations }{x}_i(1\le i\le 10)\text{ satisfy the equations, }\sum _{i=1}^{10}\left(x_i-5\right)=10\text{ and }$

$\sum _{i=1}^{10}{\left(x_i-5\right)}^2=40.\text{ If }\mu \text{ and }\lambda \text{ are the mean and variance of the observations, }$

$x_1-3,x_2-3,\dots x_{10}-3,\text{ then the ordered pair }(\mu ,\lambda )\text{ is equal to: }$

• A

  $\left(3,6\right)$

• B

  $\left(6,3\right)$

• C

  $\left(3,3\right)$

• D

  $\left(6,6\right)$