Let the observations $$xi(1$$≤i≤$$10)$$ satisfy the equations, ∑$$i=110xi-5=10$$ and ∑$$i=110xi-52=40$$. If μ and λ are the mean and variance of the observations, $$x1-3$$,$$x2-3$$,…$$x10-3$$, then the ordered pair $$($$μ,λ$$)$$ is equal to:

Question

Let the observations $$xi(1$$≤i≤$$10)$$ satisfy the equations, ∑$$i=110xi-5=10$$ and ∑$$i=110xi-52=40$$. If μ and λ are the mean and variance of the observations, $$x1-3$$,$$x2-3$$,…$$x10-3$$, then the ordered pair $$($$μ,λ$$)$$ is equal to:

Infinity Learn · Accepted Answer

Given ∑$$i=110xi=60$$ and ∑$$i=110xi2-10$$∑$$i=110xi+250=40$$⇒∑$$i=110xi2=390$$ For the observations $$x1-3$$,$$x2-3$$,…$$x10-3$$ Mean $$=$$∑$$i=110xi-310=3$$ Variance $$=$$∑$$i=110xi-3-3210=$$∑$$i=110xi-6210=$$∑$$i=110xi2-12(60)+36010=3$$

$Let the observations x_{i} (1 \leq i \leq 10) satisfy the equations, \sum_{i = 1}^{10} (x_{i} - 5) = 10 and$
$\sum_{i = 1}^{10} {(x_{i} - 5)}^{2} = 40 . If μ and λ are the mean and variance of the observations,$
$x_{1} - 3, x_{2} - 3, \dots x_{10} - 3, then the ordered pair (μ, λ) is equal to:$

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Let the observations xi(1≤i≤10) satisfy the equations, ∑i=110xi-5=10 and ∑i=110xi-52=40. If μ and λ are the mean and variance of the observations, x1-3,x2-3,…x10-3, then the ordered pair (μ,λ) is equal to:

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