Let P be any moving point on the circle x2+y2−2x=1 AB be the chord of contact of this point w.r.t. the circle x2+y2−2x=0 The locus of the circumcenter of triangle CAB (C being the center of the circle) is
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a
2x2+2y2−4x+1=0
b
x2+y2−4x+2=0
c
x2+y2−4x+1=0
d
2x2+2y2−4x+3=0
answer is A.
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Detailed Solution
Let P be (1+2cosθ,2sinθ) and C be (1,0)The circumcenter of triangle ABC is the midpoint of PC.Therefore,2h=1+2cosθ+1 and 2k=2sinθor [2(h−1)]2+(2k)2=2or 2(h−1)2+k2−1=0or 2x2+2y2−4x+1=0