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Questions  

Let P be any point on the directrix of an ellipse of eccentricity e. S be the corresponding focus and C the centre of the ellipse. The line PC meets the ellipse at A. the angle between PS and tangent at A is α , then α  is not equal to

a
tan−1e
b
π2
c
tan−1(1−e2)
d
π

detailed solution

Correct option is A

Let the ellipse be x2a2+y2b2=1  and let A≡(acosθ,bsinθ) Equation of AC will be y=batanθx. Solving with x=ae, we get P(ae,betanθ) Slope of the tangent at A is −batanθ Slope of PS=betanθae−ae=btanθa(1−e2)                                          =abtanθ                              So α=π2.

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