Let P be the image of the point (3,1,7) with respect to the plane x-y+z=3 . Then  the equation of the plane passing through P and containing the straight line x1=y2=z1is

Let P(h,k,l) be image of (3,1,7) in x-y+z=3⇒h−31=k−1−1=l−71=−263=−4     h, k, l=−1,5,3  P(-1,5,3)  now plane passing through P and  containing  the linex1=y2=z1 isx+1y−5z−31−5−3121=0⇒x−4y+7z=0