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Q.

Let P be a point in the first octant, whose image Q in the plane x+y=3 (that is, the line segment PQ is perpendicular to the plane x+y=3  and the mid-point of PQ lies in the plane x+y=3 ) lies on the z-axis. Let the distance of P from the x-axis be 5. If R is the image of P in the xy-plane, then the length of PR is

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answer is 8.

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Detailed Solution

Let P(α,β,γ) ,since Q lies on Z axis,let Q be(0,0,γ) and R is image ofP in the XY plane,so let R be=(α,β,-γ) Now, PQ¯‖i^+j^⇒(αi^+βj^)‖(i^+j^)⇒α=β  Also, mid point of PQ =α2,β2,γ lies on the plane x+y=3⇒α2+β2=3⇒α+β=6⇒α=3 Now, distance of point P from X -axis =β2+γ2=5⇒β2+γ2=25⇒γ2=16  as β=α=3  as γ=4  Hence PR=2γ=8
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