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Let P(6,3) be a point on the hyperbola $\frac{x^{2}}{b^{2}} - \frac{y^{2}}{b^{2}} = 1$ If the normal at the point P intersects the x-axis at (9, 0), then the eccentricity of the hyperbola is

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Correct option is B

x2a2−y2b2=1 or 2xa2−2yb2dydx=0 or dydx=xb2ya2 Therefore, the slope of normal at (6,3) is −a2/2b2. The equation of normal is(y−3)=−a22b2(x−6)It passes through the point (9, 0). Therefore,a22b2=1or e=32

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Let P(6,3) be a point on the hyperbolax2b2−y2b2=1 If the normal at the point P intersects the x-axis at (9, 0), then the eccentricity of the hyperbola is

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Let P(6,3) be a point on the hyperbola $\frac{x^{2}}{b^{2}} - \frac{y^{2}}{b^{2}} = 1$ If the normal at the point P intersects the x-axis at (9, 0), then the eccentricity of the hyperbola is