Let P be the point (-3, 0) and Q be a moving point (0,3t). Let PQ be trisected at R so that R is nearer to Q. RN is drawn perpendicular to PQ meeting the x-axis at N. The locus of the mid-point of RN is
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a
(x+3)2−3y=0
b
(y+3)2−3x=0
c
x2−y=1
d
y2−x=1
answer is D.
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Detailed Solution
Since R is point of trisection R⇒R divides PQ in the ratio 2:1 =2(0)+1(-3)3, 2(3t)+1(0)3 P(−3,0),Q(0,3t),R(−1,2t) Let the mid point of RN be (h,k)R(-1,2t) + N(x,y) 2=(h,k)-1+x=2h 2t+y=2kN=(2h+1,0)∴ k=t RN⊥PQ⇒2t−2h−2×3t3=−1⇒ 2t2=2h+2⇒ t2=h+1⇒ k2=h+1 Locus of (h,k) is y2=x+1