Let APa;d denote the set of all the terms of an infinite arithmetic progression with first term a and common difference d > 0. If AP1;3∩AP2;5∩AP3;7=APa;d then a + d equals_
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answer is 157.
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Detailed Solution
AP(1;3)={1,4,7,10,……….} say S1AP(2;5)={2,7,12,17,……….} say S2AP(3;7)={3,10,17,24,……….} say S3S1∩S2={7,22,37,52,…….} i.e., AP(7;15) To find the term common to AP(7;15) and AP(3;7)¯7+15l=3+7m ∴m=4+l7+2l where l,m∈W⇒l can be 3 ∴m=7 therefore the first common term =7+15l=7+153=52and the second common term =7+1510=157 since m=4+l7+2l is ∈W , then l can be =10 therefore common difference =157-52=105 ∴S1∩S2∩S3=A.P(52;105) ∴a+d=157
Let APa;d denote the set of all the terms of an infinite arithmetic progression with first term a and common difference d > 0. If AP1;3∩AP2;5∩AP3;7=APa;d then a + d equals_