Let P  1004101641  and I be  the identity matrixof  order  3. If   Q=qii  ] is a matrix such that P50−Q=I then,931+q32q21 equal

We have P=1004101641∴P2=PP=10041016411004101641=10081016+3281P3=P2P=10081016+32811004101641=100121016+32+48121By observing the symmetry, we obtain       P50=4×5010 16+32+48+…50 terms 4×501⇒ P50=1002001016×50×5122001     ∴    P50−Q=I⇒    Q=P50−I=00020000204002000⇒    q21=200,q31=20400 and q32=200∴    q31+q32q21=20400+200200=20600200=103