Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Let P1=I=100010001,P2=100001010,P3=010100001P4=010001100,P5=001100010,P6=001010100 and X=∑k=16Pk213102321PkTWhere PkT denotes the transpose of the matrix Pk. Then which of the following options is/ are correct?

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

X is a symmetric matrix

b

The sum of diagonal entries of X is 18

c

X – 30I is an invertible matrix

d

If X111=α111, then α=30

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Let A=213102321⇒X=∑k=16PkAPkT, Here PkPkT=PkTPk=I for all k=1,2,3,4,5,6 . PkT=Pk-1&AT=A and    XT=∑k=16PkAPkTT=∑k=16PkAPkT=X Let B=111⇒XB=∑K=16PKAPKTB=∑K=16PKAB=∑K=16PKAB=222222222AB=303030=30111=30B∴α=30 and (X-30I) is singular,   Tr∑k=16PkAPkT=18
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring