Q.
Let P(n):n2+n+1 is an even integer. If p(k) is assumed true ⇒P(k+1) is true. Therefore, P(n) is TRUE
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a
for n>1
b
for all n∈N
c
for n>2
d
None of the above
answer is D.
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Detailed Solution
Given,P(n):n2+n+1At n = 1, P(1):3, which is not an even integer. P(1 ) is not true (principle of induction is not applicable). Also, n(n + 1 ) + 1 is always an odd integer.
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