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Q.

Let P = P={θ :sin θ–cos θ=2cos θ} and {Q=θ:sin θ+cos θ=2sin θ} be two sets, then

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a

P⊂Q and Q~P≠ϕ

b

Q⊄P

c

P⊄Q

d

P =Q

answer is D.

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Detailed Solution

sin θ – cos θ= 2 cos θ⇔      sinθ = ( 2 +1 ) cos θ ⇔       cosθ = ( 2 -1 ) sin θ⇔        sin θ + cos θ= 2 sin θ⇒      P =Q
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