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Let P = P={θ :sin θcos θ=2cos θ} and {Q=θ:sin θ+cos θ=2sin θ} be two sets, then

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By Expert Faculty of Sri Chaitanya
a
P⊂Q and Q~P≠ϕ
b
Q⊄P
c
P⊄Q
d
P =Q
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detailed solution

Correct option is D

sin θ – cos θ= 2 cos θ⇔      sinθ = ( 2 +1 ) cos θ ⇔       cosθ = ( 2 -1 ) sin θ⇔        sin θ + cos θ= 2 sin θ⇒      P =Q


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