First slide
Theory of expressions
Question

Let p, q be integers and let  α,β be the roots of x2x1=0,  where  αβ.  For  n=0,1,2, Let  an=pαn+qβ2

Then, 

Moderate
Solution

It is given that  α and β are roots of x2x1=0

 α+β=1  and  αβ=1 

We have an=pαn+qβn

     an+1=pαn+1+qβn+1     an+1=pαn+qβn(α+β)αβpαn1+qβn1     an+1=an+an1                                [α+β=1,αβ=1]                             

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App