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: Let p and q be two statements, then ~( ~ p ∧ q ) ∧ ( p ∨ q ) is logically equivalent to

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a

q

b

p∧q

c

p

d

p∨~q

answer is C.

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Detailed Solution

~(~p∧q)∧(p∨q)≡[~(~p)∨(~q)]∧(p∨q) ≡[p∨(~q)∧(p∨q]≡p∨[(~q)∧q]≡p∨F≡p

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