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Let p and q be two statements, then $~ p \to q \land (~ q)$ is equivalent to

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p∧q

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Correct option is A

~p→q∧(~q)≡∼(~p)∨[q∧(~q)]≡p∨c≡p

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Let p and q be two statements, then ~p→q∧(~q) is equivalent to

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Let p and q be two statements, then $~ p \to q \land (~ q)$ is equivalent to