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Questions  

Let PQR be a right angled isosceles triangle right angled at P (2, 1). If the equation of the line QR is 2x + y = 3, then the equations representing the pair of lines PQ and PR is

a
x+3y=5,  3x-y=5
b
x+y=3,  x-y=1
c
2x+3y=7,  3x-2y=4
d
3x+y=7,  x-3y=-1

detailed solution

Correct option is A

Let the slopes of PQ and PR be m and -1/m respectively. Since PQR is an isosceles triangle  P Q R= PRQ m+21-2m=-1m+21+2m[∵ slope of QR = – 2]⇒ m + 2 = ± (1 – 2m) fi m = 3 or – 1/3So the equations of PQ and PR are(y-1)=3(x-2) and y-1=(-1/3)(x-2)       ⇒  3x-y=5,x+3y=5

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