Let P=(-1,0), Q=(0,0) and R=(3,33) be three points. Then the equation of the bisector of the angle PQR is
32+y=0
x+3y=0
3x+y=0
x+32y=0
Let the equation of QS, the bisector of angle PQR be y = mx.
Slope of QR=3=tan60°
⇒ PQR=120°⇒ PQS=60°
⇒m=-tan60°=-3 and thus the required equation of
the bisector to is 3x+y=0.