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Let P(x) be a polynomial of least degree whose graph has three points of inflextion (–1, –1), (1,1) and a point with abscissa 0 at which the curve is inclined to the axis of abscissas at an angle of 60

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a
1
b
2−1
c
22−1
d
none of these

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detailed solution

Correct option is D

we have P′′(x)=a(x+1)x(x−1)=ax3−x⇒P′(x)=a14x4−12x2+b⇒P(x)=a120x5−16x3+bx+cAs−1=a−120+16−b+c1=a120−16+b+c⇒c=0and 1=−760a+bAlso 3=b⇒a=60(3−1)/7we have ∫01 P(x)dx=−130a+12b=27(1−3)+32


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