Let Px be a polynomial whose coefficient are integers satisfying P(1) = 5, P (2) = 7. Then smallest possible positive value of P(10) is of the form ab then a + b = _____
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answer is 5.
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Detailed Solution
Let P(x)=q(x)(x−1)(x−2)+lx+m since P1=5⇒l+m=5 P2=7⇒2l+m=7 ⇒l=2 and m=3P(x)=q(x)(x−1)(x−2)+2x+3P(10)=q(10)⋅(72)+23 Least value of P10=23 where q(10)=0
Let Px be a polynomial whose coefficient are integers satisfying P(1) = 5, P (2) = 7. Then smallest possible positive value of P(10) is of the form ab then a + b = _____