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Let P(x)=x3+4i34ix7i5+6ix72i72i .The number of values of x for which P(x) = 0 is

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detailed solution

Correct option is B

Using R2→R2−R1,R3→R3+R1,We getP(x)=x−3+4i3−4i03−11i2+10i04+2i−4−6iAs P(x) is a linear polynomial, P(x) = 0 for exactly one value of x.


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a2b2c2(a+λ)2(b+λ)2(c+λ)2(aλ)2(bλ)2(cλ)2=kλa2b2c2abc111

λ  0 then k is equal to:


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