Questions
a
Reflexive
b
Symmetric
c
Transitive
d
Anti-symmetric
detailed solution
Correct option is B
P=(x,y)∣x2+y2=1,x,y∈R Obviously P is not reflexive, because (1,1) is not an element of R If (x,y) is an element of P then (y,x) also an element of P So, P is symmetric (0,1), (1,0) are elements of P but (0,0) is not an element of P So that the relation P is not transitive Hence, the relation P is not reflexive, symmetric, not Transitive. Therefore, the 2nd option is correctTalk to our academic expert!
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Let, Then P is
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