First slide

Relations XII

Question

Let, $P = \{(x, y) | x^{2} + y^{2} = 1, x, y \in R\} .$ Then P is

Easy

A

Reflexive
B

Symmetric
C

Transitive
D

Anti-symmetric

Solution

Obviously, the relation is not reflexive and transitive but it is symmetric, because
$x^{2} + y^{2} = 1 \Rightarrow y^{2} + x^{2} = 1 .$

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