Let the perpendiculars from any point on the line 2x+11y=5 upon the lines  24x+7y−20=0 and 4x−3y−2=0 have the lengths p1 and p2 respectively. then, p1-p2 is equal to

Let t,5−2t11 be a point on the line 2x+11y=5.Then,p1=24t+75−2t11−20242+72=|50t−37|55and p2=4t−35−2t11−242+(−3)2=|50t−37|55Clearly, we have p1=p2ALITER: Clearly, 2x+11y=5  is the angle bisector of the two lines. Therefore p1=p2