Let PM be the perpendicular from the point P(1,2,3) to the x-y plane .lf OP→ makes an angle θ with the positive direction of the z-axis and OM→ makes an angle ϕ with the positive direction of x-axis, where O is the origin and θ and ϕ are acute angles, then
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a
cosθcosϕ=1/14
b
sinθsinϕ=2/14
c
tanϕ=2
d
tanθ=53
answer is B.
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Detailed Solution
If P be (x, y, z), then from the figure, x=rsinθcosϕ,y=rsinθsinϕ and z=rcosθ1=rsinθcosϕ,2=rsinθsinϕ and 3=rcosθ⇒ 12+22+32=r2 or r=±14∴ sinθcosϕ=114,sinθsinϕ=214 and cosθ=314(neglecting negative sign as θ and ϕ are acute) sinθsinϕsinθcosϕ=21Also, tanθ=53