Let p(n) denote the statement that n2 + n is odd. It is seen that p(n) ⇒ p(n + 1), P(n) is true for all

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n>1

n>2

None of these

answer is D.

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Detailed Solution

Since the square of any odd number is always odd an sum of two odd numbers is always even, so for no ‘n’ this statement is true.

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