Let P(n) denotes the statement that n2 + n is odd. It is seen that P(n) ⇒ P( n + 1), P(n) is true for all
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a
n>1
b
n
c
n>2
d
None of these
answer is D.
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Detailed Solution
P(n)=n2+nIt is always odd but square of any odd number is always odd and also sum of two odd number is always even. So, for no any n for which this statement is true.