Q.

Let PS be the median of the triangle with ertices P (2, 2), Q (6, -1) and R (7, 3). The equation of the line passing through (1, -1) and parallel to PS, is

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a

2x-9y=7

b

2x-9y-11=0

c

2x+9y-11=0

d

2x+9y+7=0

answer is D.

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Detailed Solution

The coordinates of S are6+72,−1+32=132,1Slope of PS=1−2132−2=−29Equation of a line passing through (1, -1) and parallel to PS is y+1=−29(x−1)⇒2x+9y+7=0
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Let PS be the median of the triangle with ertices P (2, 2), Q (6, -1) and R (7, 3). The equation of the line passing through (1, -1) and parallel to PS, is