Let PS be the median of the triangle with ertices P (2, 2), Q (6, -1) and R (7, 3). The equation of the line passing through (1, -1) and parallel to PS, is
2x-9y=7
2x-9y-11=0
2x+9y-11=0
2x+9y+7=0
The coordinates of S are
6+72,−1+32=132,1
Slope of PS=1−2132−2=−29
Equation of a line passing through (1, -1) and parallel to PS is
y+1=−29(x−1)⇒2x+9y+7=0