Let Q be the foot of the perpendicular from theorigin O to the tangent at a point p(α,β) on the
parabola y2=4ax, and Sbe the focus of the parabola,then (OQ)2(SP) is equal to
α
aα2
β
aβ2
Let α=at2,β=2at
Equation of the tangent at P(α,β) is ty=x+at2
⇒OQ=at21+t2SP=at2+1 So (OQ)2(SP)=a2t41+t2×a1+t2=a3t4=aα2