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Questions  

Let Q be the foot of the perpendicular from the
origin O to the tangent at a point p(α,β) on the 

parabola y2=4ax,  and Sbe the focus of the parabola,
then (OQ)2(SP) is equal to

a
α
b
aα2
c
β
d
aβ2

detailed solution

Correct option is B

Let α=at2,β=2atEquation of the tangent at P(α,β)  is ty=x+at2⇒OQ=at21+t2SP=at2+1 So (OQ)2(SP)=a2t41+t2×a1+t2=a3t4=aα2

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