Let R be a relation defined by R={(a,b):a≥b}, where a and b are real numbers, then R is
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a
reflexive, symmetric and transitive
b
reflexive, transitive but not symmetric
c
symmetric, transitive but not reflexive
d
neither transitive, nor reflexive, not symmetric
answer is B.
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Detailed Solution
R={(a,b):a≥b}We know that, a≥a∴ (a,a)∈R,∀a∈RR is a reflexive relation. Let (a,b)∈R⇒ a≥b⇒ b≤a⇒ (b,a)∉RSo, R is not symmetric relation.Now , let (a,b)∈R and (b,c)∈R⇒a≥b and b≥c⇒a≥c⇒(a,c)∈RR is a transitive relation.