Let R be a relation defined on the set of real numbers by aRb⇔$$1+ab$$>$$0$$. Then R is

Correct option is 1reflexive, symmetric, but not transitive

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Let R be a relation defined on the set of real numbers by $a R b \Leftrightarrow 1 + a b > 0$ . Then R is

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reflexive, symmetric, but not transitive

symmetric, transitive, but not reflexive

symmetric, not reflexive, not transitive

reflexive, anti symmetric, not transitive

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detailed solution

Correct option is A

1+a2>0 ∀a∈R ⇒a,a∈R ⇒R is reflexive if 1+ ab>0 then 1+ba>0⇒R is symmetric here (−2,0)∈R and _ (0,3)∈R but (−2,3)∉R ∴R is not transitive

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Let R be a relation defined on the set of real numbers by aRb⇔1+ab>0. Then R is

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

Let R be a relation defined on the set of real numbers by $a R b \Leftrightarrow 1 + a b > 0$ . Then R is