First slide
Relations XII
Question

Let A=1, 2, 3, 4 and R be a relation in A given by R=1, 1, 2, 2, 3, 3, 4, 4, 1, 2, 2, 1, 3, 1, 1, 3.

Then R is

Easy
Solution

1, 22, 23, 34, 4R; R is reflexive.

1, 2 3, 1R and also 2, 11, 3R.

Hence, R is symmetric. But clearly R is not transitive.

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