First slide
Relations XII
Question

 Let R be the relation on the set of all real numbers defined  by aRb iff |ab|1 . Then, R is 

Moderate
Solution

|aa|=0<1aRaaR

Therefore, R is reflexive.

 Again aRb|ab|1 and ba∣≤1bRa

Therefore, R is symmetric. 

 Again 1R12 and 12R1 but 121

Therefore, R is not anti-symmetric. 

 Further, 1R2 and 2R3 but 1R3,[|13|=2>1]

Therefore, R is not transitive.
 

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