Let R be a relation on the set N be defined by x, y|x, y∈N, 2x+y=41. Then R is

On the set N of natural numbers,R=x, y: x, y∈N, 2x+y=41.Since 1, 1∉R as 2.1+1=3≠41. So, R is not reflexive. 1, 39∈R but 39, 1∉R.So R is not symmetric 20, 1,(1, 39)∈R. But 20, 39∉R, So R is not transitive.