Let R be a relation on the set N be defined by {(x,y)∣x , y∈N,2x+y=41}. Then, R is
Reflexive
Symmetric
Transitive
None of these
On the set N of natural numbers, R={(x,y);x,y∈N,2x+y=41}
As (1,1)∉R as 2.1+1=3≠41. So, R is not reflexive.
(1,39)∈R but (39,1)∉R. So, R is not symmetric.
(20,1)(1,39)∈R, but (20,39)∉R. So, R is not transitive.