. Let R be a relation on the set N of natural numbers denoted by nRm⇔n is a factor of m (i$$.e., n∣$$m) . Then, R is

Correct option is 4Reflexive, transitive but not symmetric

Questions

. Let R be a relation on the set N of natural numbers denoted $by n R m \Leftrightarrow n is a factor of m (i.e., n ∣ m) . Then, R is$

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Reflexive and symmetric

Transitive and symmetric

Equivalence

Reflexive, transitive but not symmetric

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detailed solution

Correct option is D

As n∣n for all n∈N,R is reflexive. As 2|6 but 6∣2,R is not symmetric Let nRm and mRp. As n∣m and m|p⇒n|p⇒nRp . So, R is transitive.

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. Let R be a relation on the set N of natural numbers denoted by nRm⇔n is a factor of m (i.e., n∣m) . Then, R is

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

. Let R be a relation on the set N of natural numbers denoted $by n R m \Leftrightarrow n is a factor of m (i.e., n ∣ m) . Then, R is$