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Let R be a relation on a set A such that $R = R^{- 1}$ , then R is

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Correct option is B

Let (a, b)∈R⇒(b, a)∈R-1, [By def. or R-1]⇒(b, a)∈R, [∵ R=R-1]So, R is symmetric.

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Let R be a relation on a set A such that R=R-1, then R is

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Let R be a relation on a set A such that $R = R^{- 1}$ , then R is