Let R and S be two non-void relation in a set A. Which of the following statements is false?
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a
R and S transitive ⇒R∪S is transitive
b
R and S transitive ⇒R∩S is transitive
c
R and S symmetric ⇒R ∪S is symmetric
d
R and S reflexive⇒ R ∩S is reflexive
answer is A.
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Detailed Solution
Let (a, b), (b, c), ∈(R∪S).It is possible that (a, b)∈R - S and (b, c)∈S - R.In such a case, We cannot say that (a, c) ∈R or (a, c) ∈S∴ (a, c) may not be in R∪S.∴ R∪S is not transitive.(b) Let (a, b), (b, c)∈R∩S.∴ (a, b), (b, c) ∈ R and (a, b), (b, c)∈S∴ (a, c)∈R and (a, c)∈S∴(a, c)∈R∩S(C) Let (a, b) ∈R∪S∴ (a, b)∈R or (a, b) ∈SNow, (a, b) ∈R ⇒(b, a)∈R (∵ R is symmetric) (a, b) ∈S⇒( b- a)∈S (∵S is symmetric)∴R∪S is symmetric.(d) Let a ∈ A.∴ ( a, a)∈R and (a, a)∈S ∴ (a, a) ∈R∩S∴R ∩ S is reflexive