Let $$R={(x$$,$$y)$$:x,y∈A,$$x+y=5}$$ $$whereA={1$$, $$2$$, $$3$$, $$4$$, $$5}$$ then

Correct option is 1R is not reflexive, symmetric and not transitive

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Let $R = {(x, y) : x, y \in A, x + y = 5}$ where
$A = {1, 2, 3, 4, 5}$ then

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detailed solution

Correct option is A

R={(1,4), (4,1), (2,3), (3,2)} so R is not reflexive as (1,1)∉R⋅R is symmetric by definition and R isnot transitive as (1,4)∈R,(4,1)∈R but (1,1)∉R.

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Let R={(x,y):x,y∈A,x+y=5} whereA={1, 2, 3, 4, 5} then

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Let $R = {(x, y) : x, y \in A, x + y = 5}$ where
$A = {1, 2, 3, 4, 5}$ then