Let R={(x,y):x,y∈R,x2+y2≤25} R'={(x,y):x,y∈R,y≥(4/9)x2} then
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a
dom R∩R'=[−3,3]
b
Range R∩R'⊃[0,4]
c
Range R∩R'=[0,5]
d
R∩R' defines a function
answer is A.
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Detailed Solution
The equation x2+y2=25 represent a circle with centre (0,0) and radius 5 and the equation y=49x2 represent a parabola with vertex (0,0) and focus (0,916). Hence R∩R' is the set of points indicated in the Fig.={(x,y):−3≤x≤3,0≤y≤5}.Thus dom R∩R'=[−3,3] and range R∩R'=[0,5]⊃[0,4]Since (0,0)∈R∩R' and (0,5)∈R∩R'Hence R∩R' doesn’t defines a function.