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Let S=18ab25:a,bN The number of singular matrices in s is

 

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a
18
b
25
c
450
d
infinite

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detailed solution

Correct option is A

det 18ab25=2×32×52−ab=0    ⇔    ab=    2×32×52    ⇔        a∣2×32×52That is a is a divisor of 2×32×52Therefore, a is of the form 2a3b52 whereα∈{0,1},β,γ∈{0,1,2}.Thus number of elements in  S is 2×3×3=18.


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