First slide
Combinations
Question

Let S=18ab25:a,bN The number of singular matrices in s is

 

Moderate
Solution

det 18ab25=2×32×52ab=0

        ab=    2×32×52            a2×32×52

That is a is a divisor of 2×32×52

Therefore, a is of the form 2a3b52 where

α{0,1},β,γ{0,1,2}.

Thus number of elements in  S is 2×3×3=18

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App