Let $$S1$$ be the sum of the first n terms of the A.P. $$8$$,$$12$$,$$16$$………… and let $$S2$$ be the sum of the first n terms of the A.P $$17$$,$$19$$,$$21$$…………, assume n≠$$0$$, then $$S1=S2$$ for:

Correct option is 2one value of n

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$Let S_{1} be the sum of the first n terms of the A.P. 8, 12, 16 \dots \dots \dots \dots and let$ $S_{2} be the sum of the first n terms of the A.P 17, 19, 21 \dots \dots \dots \dots, assume n \neq 0,$ $then S_{1} = S_{2} for:$

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detailed solution

Correct option is B

n2[2.8+(n−1)4]=n2[2.17+(n−1)2]n[8+2(n−1)]=n(17+n−1)2n2+6n=n2+16nn2−10n=0n=0 (impossible) n=10

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Let S1 be the sum of the first n terms of the A.P. 8,12,16………… and let S2 be the sum of the first n terms of the A.P 17,19,21…………, assume n≠0, then S1=S2 for:

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$Let S_{1} be the sum of the first n terms of the A.P. 8, 12, 16 \dots \dots \dots \dots and let$ $S_{2} be the sum of the first n terms of the A.P 17, 19, 21 \dots \dots \dots \dots, assume n \neq 0,$ $then S_{1} = S_{2} for:$