Let S(K):1+3+5+…+(2K−1)=3+k2
Then which of the following is true?
S(K)≠S(K+1)
S(K)⇒S(K+1)
S(1) is correct
principle of mathematical induction can be used to prove the formula
S(1):1=3+12 which is not true. Suppose
S(K) is true, then
1+3+5+…+(2K−1)=3+K2
Adding (2K + 1) to both the sides, we get
1+3+5+…+(2K−1)+(2K+1)=3+K2+2K+1=3+(K+1)2
which is S (K + 1)
Thus, S(K) fi S(K + 1).