Let Sn denote the sum of first n-terms of an A.P. If S4=16,S6=−48 thenS10is

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answer is 320.

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Detailed Solution

S4=22a+3d=16 Sn=n22a+n-1d→2a+3d=8−−1S6=3[2a+5d]=−482a+5d=−16−−−22−1⇒d=−12⇒2a=44a=22S10=102[2a+9d]=5[44+9(−12)]=5(44−108)=−320, S10=320

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