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Let $S_{n} = \sum_{r = 1}^{n} r!; (n > 6) . Then, S_{n} - 7 [\frac{S_{n}}{7}]$ (where, [ . ] denotes greatest integer function) is equal to

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Correct option is C

All numbers r! (r ≥7) will be multiple of 7.So, for remainder considerS6=1+2+6+24+120+720=873which leaves the remainder 5, when divided by 7

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Let Sn=∑r=1n r!;(n>6). Then, Sn−7Sn7 (where, [ . ] denotes greatest integer function) is equal to

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Let $S_{n} = \sum_{r = 1}^{n} r!; (n > 6) . Then, S_{n} - 7 [\frac{S_{n}}{7}]$ (where, [ . ] denotes greatest integer function) is equal to