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Correct option is B
Given S1+S2+…+S10=t1+t2+…+t15 Let first sequence a1,a1+d1,a1+2d1,… and second sequence is a1,a1+d2,a2+2d2,… (sinc s1=t1) Given S2=2t2a1+d1=2a1+d2a1=d1−2d2−−−1 We have to find ⇒S2−S1t2−t1=d1d2 Now 1022a1+9d1=1522at1+14d2⇒a1=9d1−21d2−⋯−2 For 1 and 2⇒d1−2d2=9d1−21d28d1=19d2d1d2=198Similar Questions
If the sum of first terms of an is , then the sum of squares of these terms is
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