Let S1,S2,S3… and t1,t2,t3… are two Arithmatic Sequence such that S1=t1≠0,S2=2t2 and ∑i=110 Si=∑i=115 ti then S2−S1t2−t1=d1d2 then d1−d2=

Given S1+S2+…+S10=t1+t2+…+t15 Let first sequence a1,a1+d1,a1+2d1,… and second sequence is a1,a1+d2,a2+2d2,… (sinc s1=t1) Given S2=2t2a1+d1=2a1+d2a1=d1−2d2−−−1 We have to find ⇒S2−S1t2−t1=d1d2 Now 1022a1+9d1=1522at1+14d2⇒a1=9d1−21d2−⋯−2 For 1 and 2⇒d1−2d2=9d1−21d28d1=19d2d1d2=198