Let A=3 21 1 satisfies A2+aA+bI=O, then a, b are respectively equal to
– 4, 2
–3, 3
– 4, 1
–3, 1
A2=3 21 13 21 1=11 84 3
Now O=A2+aA+bI=11+3a+b8+2a4+a3+a+b
⇒ 3a+b=−11,4+a=0,a+b=−3⇒ a=−4,b=1.