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$Let A = \sin^{8} θ + \cos^{14} θ,then for all real θ$

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A≥1

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Correct option is B

We know that 0≤sin2θ≤1⇒sin8θ≤sin2θAlso cos14θ≤cos2θOn adding cos14θ+sin8θ≤1∴0

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Let A=sin8θ+cos14θ ,then for all real θ

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$Let A = \sin^{8} θ + \cos^{14} θ,then for all real θ$