First slide
Introduction to Determinants
Question

Let Δ=1sinθ1sinθ1sinθ1sinθ1,0θ2π. The

Moderate
Solution

Applying R1R1+R3 to obtain 

Δ=002sinθ1sinθ1sinθ1=2sin2θ+1

As, 0sin2θ1, we get Δ[2,4]

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