Let (sina)x2+(sina)x+1−cosa=0 The set of values of a for which roots of this equation are real and distinct, is
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a
(0, 2tan−114)
b
0,2π3
c
(0, π)
d
(0, 2π)
answer is A.
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Detailed Solution
The roots of the given equation will be real and distinct, iff sin2a−4sina(1−cosa)>0⇒(1−cosa){1+cosa−4sina}>0⇒2cos2a2−8sina2cosa2>0⇒2cos2a2(1−4tana2)>0⇒4tana2<1⇒−π2