Let (sina)x2+(sina)x+1−cosa=0 The set of values of a for which roots of this equation are real and distinct, is
(0, 2tan−114)
0,2π3
(0, π)
(0, 2π)
The roots of the given equation will be real and distinct, iff
sin2a−4sina(1−cosa)>0⇒(1−cosa){1+cosa−4sina}>0⇒2cos2a2−8sina2cosa2>0⇒2cos2a2(1−4tana2)>0⇒4tana2<1⇒−π2<a2<tan−114⇒−π<a<2tan−114
Hence, option (a) is correct.