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 Let Tr be the rth  term of an A.P. Whose first term is a and common  difference is d. If for some positive integers m,n,mn,Tm=1n and Tn=1m and ad equals: 

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a
0
b
1
c
1mn
d
1m+1n

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detailed solution

Correct option is A

Tm=a+(m−1)d=1nTn=a+(n−1)d=1m (m−n)d=1n−1m=(m−n)mn So,  d=1mn a=1n−(m−1)d=1n−(m−1)1mn=1mna−d=0


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